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Arithmetic Progressions |
Geometric Progressions |
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Example: 3, 7, 11, 15, ...
The first term = a = 3
The common difference = d = 4
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Example: 3, 6, 12, 24, ...
The first term = a = 3
The common ratio = r = 2 |
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d = u n - u n-1 |

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A general Arithmetic Progression :
a, a + d, a + 2d, a + 3d, .... , a + (n - 1)d
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A General Geometric Progression :
a, a r 2, a r 3, a r 4,
... , a r n-1 |
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u n = a + (n - 1)d
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u n = a r
n-1 |
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To find the sum of an Arithmetic Progression (S
n):
Sn = a + a + d + a +2d + ... + a+(n-1)d
Sn = a+(n-1)d + a+(n-2)d + a+(n-3) + ... + a
2Sn = 2a+(n-1)d +2a+(n-1)d + 2a+(n-1)d +... + 2a+(n-1)d
2Sn = n(2a + n-1)d

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To find the sum of a Geometric Progression (S
n)
S n = a + a r + a r2 + a r3 + ...+ a r
n-1
r S n = a r + a r2 + a r3 + ...+ a r
n-1 + a r n
S n - r S n = a - a r n
S n (1 - r) = a(1 - r n)

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3 Consecutive Terms of an arithmetic Progression
x - d, x, x + d |
3 Consecutive Terms of a Geometric Progression

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To prove a sequence is arithmetic:
Show that u n - u n-1 = a
constant
(i.e. u n - u n-1 is independent of
n) |
To prove a sequence is geometric:
Show that = a constant (i.e.
independent of n) |
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To find u n given S n
U n = S n - S n-1
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To find u n given S n
U n = S n - S
n-1 |
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To find a and d when given two terms:
e.g. If u 2 = 5 and u 4 = 11 find a
and d.
u 2 = a + (2 - 1)d u 4 = a + (4 -
1)d
5 = a + d 11 = a + 3d
Simultaneous equations gives a = 3 and d = 2 |
To find a and r when given two terms :
e.g. If u 3 = 2 and u 6 = 16 find a
and r.
u3 =a r 2 = 2 u6
= a r 5 = 16

r = 2 and a = 1
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Arithmetic mean
The arithmetic mean of two numbers is that number that
when placed between two numbers, forms three consecutive terms of an
arithmetic progression.
e.g. the arithmetic mean of the numbers a and b is

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Geometric Mean
If a, b and c are in geometric progression then

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Sum to infinity of a geometric progression:
If |r| < 1 then

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